Solution: What is the shortest distance from A(3, 8) to the circle x^2 + y^2 + 4x – 6y = 12?

The shortest distance from A(3, 8) to the circle x^2 + y^2 + 4x – 6y = 12 is equal to? How to find the shortest distance from a point to the circle?

What is the shortest distance from A(3, 8) to the circle x^2 + y^2 + 4x – 6y = 12?

Problem Statement: CE Board November 1993

What is the shortest distance from A(3, 8) to the circle x^2 + y^2 + 4x – 6y = 12?

Problem Answer:

The shortest distance from A(3, 8) to the circle is 2.1 units.

Solution:

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