Solution: The equation 25x^2 + 16y^2 – 150x + 128y + 81 = 0 has its center at?

The equation 25x^2 + 16y^2 – 150x + 128y + 81 = 0 has its center at? How to find the center of the circle given the equation?

The equation 25x^2 + 16y^2 – 150x + 128y + 81 = 0 has its center at?

Problem Statement:

The equation 25x^2 + 16y^2 – 150x + 128y + 81 = 0 has its center at?

Problem Answer:

The cener of the equation of the circle is (3, -4).

Solution:

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