Solution: The equation x^2 + y^2 – 4x + 2y – 20 = 0 describes

The equation x^2 + y^2 – 4x + 2y – 20 = 0 describes:

The equation x^2 + y^2 – 4x + 2y – 20 = 0 describes:

Problem Statement: ME Board October 1996

The equation x^2 + y^2 – 4x + 2y – 20 = 0 describes:

Problem Answer:

The equation describes a a circle of radius 5 centered at (2, -1).

Solution:

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