Solution: Simplify the following: [(cos⁡ A+cos⁡ B)/(sin A-sin ⁡B) + (sin⁡ A+sin ⁡B)/(cos⁡ A-cos⁡ B)]

Simplify the following: [(cos⁡ A+cos⁡ B)/(sin A-sin ⁡B) + (sin⁡ A+sin ⁡B)/(cos⁡ A-cos⁡ B)]

Simplify the following: [(cos⁡ A+cos⁡ B)/(sin A-sin ⁡B) + (sin⁡ A+sin ⁡B)/(cos⁡ A-cos⁡ B)]

Problem Statement: ECE Board April 1991

Simplify the following: [(cos⁡ A+cos⁡ B)/(sin A-sin ⁡B) + (sin⁡ A+sin ⁡B)/(cos⁡ A-cos⁡ B)]
  • A. 0
  • B. sin A
  • C. 1
  • D. cos A

Problem Answer:

The equivalent value is 0

Solution:

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