Solution: Given log 6 + x log 4 = log 4 + log (32 + 4^x). Find x

Given log 6 + x log 4 = log 4 + log (32 + 4^x). Find x. How to find the value of x in the logarithmic equation?

Given log 6 + x log 4 = log 4 + log (32 + 4^x). Find x.

Problem Statement: EE Board October 1992

Given log 6 + x log 4 = log 4 + log (32 + 4^x). Find x.
  • A. 2
  • B. 3
  • C. 4
  • D. 6

Problem Answer:

The value of x is equal to 3.

Solution:

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