Solution: What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)?

What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)? How to find the equation of the line normal to the curve at the given point?

What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)?

Problem Statement: CE Board May 1995

What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)?

Note: The slope of the line normal to the curve at the given point is equal to the negative of the reciprocal of the slope of the given curve.

Problem Answer:

The equation of the normal to the curve is equal to 3x – 4y = 0

Solution:

Online Questions and Answers in Differential Calculus (LIMITS & DERIVATIVES)


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