# Solution: What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)?

What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)? How to find the equation of the line normal to the curve at the given point?

#### Problem Statement: CE Board May 1995

What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)?

Note: The slope of the line normal to the curve at the given point is equal to the negative of the reciprocal of the slope of the given curve.

• A. 5x + 3y = 0
• B. 3x – 4y = 0
• C. 3x + 4y = 0
• D. 5x – 3y = 0

The equation of the normal to the curve is equal to 3x – 4y = 0

Solution:

### Latest Problem Solving in Differential Calculus (LIMITS & DERIVATIVES)

More Questions in: Differential Calculus (LIMITS & DERIVATIVES)

#### Search! Type it and Hit Enter

 Accepting Contribution for Website Operation. Thanks! Option 1 : \$5 USD Option 2 : \$10 USD Option 3 : \$15 USD Option 4 : \$20 USD Option 5 : \$25 USD Option 6 : \$50 USD Option 7 : \$100 USD Option 8 : Other Amount