# Solution: If dy = x^2 dx; what is the equation of y in terms of x if the curve passes through (1, 1)

If dy = x^2 dx; what is the equation of y in terms of x if the curve passes through (1, 1). How to find the equation of y in terms of x?

#### Problem Statement: EE Board October 1997

If dy = x2 dx; what is the equation of y in terms of x if the curve passes through (1, 1).

• A. x2 – 3y + 3 = 0
• B. x3 – 3y + 2 = 0
• C. x3 + 3y2 + 2 = 0
• D. 2y + x3 + 2 = 0

The equation of y in terms of x is x3 – 3y + 2 = 0

Solution:

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