# Solution: Find the sum of the ages of John and Mark

JJ is 3 times as old as Jan-Jan. Three years ago, JJ was four times as old as Jan-Jan. The sum of their ages is? How to solve age problems?

#### Problem Statement:

John is 3 times as old as Mark. Three years ago, John was four times as old as Mark. The sum of their ages is?

The sum of their ages is 36 years.

Solution:

### Latest Problem Solving in Age, Work, Mixture, Digit, Motion Problems

More Questions in: Age, Work, Mixture, Digit, Motion Problems

#### Search! Type it and Hit Enter

 We educate thousands of students a week in preparation for their licensure examinations. We provide professionals with materials for their lectures and practice exams. To help us go forward with the same spirit, contribution from your side will highly appreciated. Thank you in advance. Option 1 : \$5 USD Option 2 : \$10 USD Option 3 : \$15 USD Option 4 : \$20 USD Option 5 : \$25 USD Option 6 : \$50 USD Option 7 : \$100 USD Option 8 : Other Amount