Review: Problem Solving in IsometricProcess 01

A perfect gas has a value of R = 766.54 ft.lbf/lbm - °R and k = 1.26. If 30 Btu are added to 5 lbm of this gas at constant volume when the initial temperature is 95°F, find (a) T2 (b) Change in H (c) Change in S (d) Change in U (e) Work for a non flow process.

Review: Problem Solving in IsometricProcess 01

Problem Statement:

A perfect gas has a value of R = 766.54 ft.lbf/lbm - °R and k = 1.26. If 30 Btu are added to 5 lbm of this gas at constant volume when the initial temperature is 95°F, find (a) T2 (b) Change in H (c) Change in S (d) Change in U (e) Work for a non flow process.

Course: Thermodynamics

TOPIC: Processes of Ideal Gas

SUBTOPIC: Isometric Process

DEFINITION: An Isometric Process is a reversible constant volume process. A constant volume process maybe reversible or irreversible.

Problem Answer:

a.) T2 = 556.22°R b.) ∆H = 41.97 BTU c.) ∆S = 0.049 BTu/°R d.) ∆U = 30 BTu e.) W = 0

Solution:

Latest Problem Solving in Thermodynamics

More Questions in: Thermodynamics

Online Questions and Answers in Thermodynamics


Search! Type it and Hit Enter


We educate thousands of students a week in preparation for their licensure examinations. We provide professionals with materials for their lectures and practice exams. To help us go forward with the same spirit, contribution from your side will highly appreciated. Thank you in advance.


Post a Comment

Contact Form

Name

Email *

Message *

Powered by Blogger.
Javascript DisablePlease Enable Javascript To See All Widget
Real Time Web Analytics