A beam of span ‘x’ meters with uniform loading of ‘w’ kilograms per meter is supported at one end (A) and a distance of 2 m from the other end (B). Find the reaction at support A.
- A. (wx^2)/ [2(x-2)] kg
- B. [wx(x-4)]/[2(x-2)] kg
- C. [wx(x-2)]/[2(x-2)] kg
- D. wx/[2(x-2)] kg
The reaction at support A is [wx(x-4)]/[2(x-2)] kg.Solution: