Solution: Find the value of A in the equation: (x^2+4x+10)/(x^3+2x^2+5x) = A/x + B(2x+2)/(x^2+2x+5) + C/(x^2+2x+5)

Find the value of A in the equation: (x^2+4x+10)/(x^3+2x^2+5x) = A/x + B(2x+2)/(x^2+2x+5) + C/(x^2+2x+5). How to solve for the value of A in the partial fraction?

Find the value of A in the equation: (x^2+4x+10)/(x^3+2x^2+5x) = A/x + B(2x+2)/(x^2+2x+5) + C/(x^2+2x+5).

Problem Statement: CE Board May 1996

Find the value of A in the equation: (x^2+4x+10)/(x^3+2x^2+5x) = A/x + B(2x+2)/(x^2+2x+5) + C/(x^2+2x+5).
  • A. -2
  • B. 1/2
  • C. -1/2
  • D. 2

Problem Answer:

A is equal to 2.

Solution:

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